2/x-16-3x/x^2-225=4/x+15

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Solution for 2/x-16-3x/x^2-225=4/x+15 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

2/x-((3*x)/(x^2))-225-16 = 4/x+15 // - 4/x+15

2/x-((3*x)/(x^2))-(4/x)-225-16-15 = 0

2/x-3*x^-1-4*x^-1-225-16-15 = 0

-5*x^-1 = 256 // : -5

x^-1 = -256/5

-1 < 0

1/(x^1) = -256/5 // * x^1

1 = -256/5*x^1 // : -256/5

-5/256 = x^1

x = -5/256

x = -5/256

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